Construct a quadrilateral ABCD in which BC = 7.5 cm, AC =AD = 6 cm, CD = 5 cm and BD = 10 cm.
As three sides and two diagonals of quadrilateral is given.
Step 1-Using SSS construction condition first we will draw ΔBCD. Draw line BD of length 10 cm.

Step 2- Then using compass take a length of 7.5 cm and draw an arc by taking B as centre. Do the same by taking D as centre and length of 5 cm.
Step 3-Now join the intersection point to B and D and label it as C.

Step 4- Now for vertex A, using compass take a length of 6 cm and draw an arc by taking C as centre. Do the same by taking D as centre and length of 6 cm.

Step 5-Join the intersection point to B and D and label it as A.

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