Two particles have equal momenta. What is the ratio of their de-Broglie wavelengths?
OR
Monochromatic light of frequency 6.0x 1014 Hz is produced by a laser. What is the energy of a photon in the light beam?
Given: -
Two particles have equal momenta ‘p’
Formula: -
the de Broglie wavelength associated with a given particle is,
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Where λ is the de-Broglie wavelength of the particle, h is the Planck’s constant and p is the momentum.
So, we can write the ratio as

(∵p1 = p2 = p)
Conclusion: -
The ratio of de-Broglie wavelengths is 1.
OR
Given: -
Frequency of Monochromatic light, v = 6.0x 1014 Hz
Formula: -
We know that the energy of a photon is given by the equation,
E = h v
Where, E is the energy of the photon,
h is the Planck’s constant and,
v is the frequency.
So, substituting the values we get,
E = 6.626 × 10-34 × 6 × 1014= 39.756 × 10-20 J.
Conclusion: -
The energy of the light is, E = 3.9756 × 10-19 J.
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