Q3 of 805 Page 13

Construct a ΔABC in which BC = 6.5 cm, AB = 4.5 cm and ABC = 60°. Construct a triangle similar to this triangle whose sides are of the corresponding sides of ABC.


Steps of Construction:


1. Draw a line segment BC = 6.5 cm.



2. Construct YBC = 60°.



3. Mark an arc from B of length 4.5 cm which cuts YB at A.



4. Join AC.



5. Δ ABC is the required triangle.


6. Draw a ray BX on the side opposite to the vertex A.



7. Along BX, mark 4 points B1, B2, B3 and B4.



8. Join B4C.



9. Draw B3C’ parallel to B4C such that C’ lies on BC.



10. Draw A’C’ parallel to AC such that A’ lies on AB.



Δ A’BC’ is the triangle whose sides are times the corresponding sides of Δ ABC.


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