Construct a ΔPQR, in which PQ = 6 cm, QR = 7 cm and PR = 8 cm. Then, construct another triangle whose sides are times the corresponding sides of ΔPQR.

Steps of Construction:

1. Draw a line segment QR = 7 cm.

2. With Q as centre and radius 6 cm, draw an arc.

3. With R as centre and radius 8 cm, draw an arc cutting the previous arc at P.

4. Join PQ and PR. Thus, ΔPQR is the required triangle.

5. Below QR, draw an acute angle ∠RQX.

6. Along QX, mark five points R₁, … R₅ such that QR₁ = R₁R₂ .. = R₄R₅.

7. Join RR₅.

8. From R₄, draw R₄R’ || RR₅ meeting QR at R’.

9. From R’, draw P’R’ || PR meeting PQ at P’.

Here, ΔP’QR’ is the required triangle each of whose sides are times the corresponding sides of ΔPQR.