Q6 of 805 Page 11

Let ABC be a right triangle in which AB = 6 cm, BC = 8 cm and ∠ B = 90°. BD is the perpendicular from B on AC. The circle through B, C, D is drawn. Construct the tangents from A to this circle.


BC= diameter


∠BDC=90°


Center of circle=E, midpoint of BC


Step1: Join AE and bisect.


F is midpoint of AE


Step2: Now draw a circle of FE radius, F as a center. Join AG.


AB and AG are tangents.



Justification:


Join EC.


(angle is on semicircle)


(EG=radius and AG=tangent)



(BE=radius and AB=tangent)


More from this chapter

All 805 →
4

Draw a pair of tangents to a circle of radius 5 cm which are inclined to each other at an angle of 60°.

 5

Draw a line segment AB of length 8 cm. Taking A as Center, draw a circle of radius 4 cm and taking B as center, draw another circle of radius 3 cm. Construct tangents to each circle from the Center of the other circle.

 7

Draw a circle with the help of a bangle. Take a point outside the circle. Construct the pair of tangents from this point to the circle.

 1

Two line segment AB and AC include an angle of 60°, where AB=5cm and AC=7cm. Locate points P and Q on AB and AC, respectively such that AP= 3/4 AB and AQ= 1/4 AC. Join P and Q and measure the length PQ.