Q14 of 805 Page 11

Construct a triangle with sides 5 cm, 5.5 cm and 6.5 cm. Now construct another triangle, whose sides are 3/5 times the corresponding sides of the given triangle.

The steps involved in the required construction are:

1) Draw a line segment BC=5 cm.



2) Taking B as the center and radius 5.5 cm, draw an arc. Now taking C as the center and radius 6.5 cm draw another arc, intersecting the previous arc at A. Join AB and AC.



3) Draw any line segment BD, making an acute angle with BC and opposite to the vertex A. Taking B as the center and any radius, draw an arc, intersecting BD at E. Taking E as the center and radius BE, draw an arc, intersecting BD at F. Similarly, repeat the process 3 more times to get points G, H and I. Join CI.



4) Taking I as the center and any radius, draw an arc., intersecting BD and CI at J and K respectively. Taking G as the center and radius IJ, draw an arc., intersecting BD at L. Taking L as the center and radius JK, draw an arc, intersecting previous arc at M. Join and extend GM, intersecting BC at N.



5) Taking C as the center and any radius, draw an arc., intersecting BC and CA at P and Q respectively. Taking N as the center and radius CP, draw an arc., intersecting BC at R. Taking R as the center and radius PQ, draw an arc, intersecting previous arc at S. Join and extend NS, intersecting AB at O.



6) ∆BNO is the required triangle.


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