Construct a quadrilateral ABCD where AB = 5.5 cm, BC = 3.7 cm, ∠A = 60°, ∠B = 105° and ∠D = 90°.

We know that sum of all angles in a quadrilateral is 360⁰

+ + + = 360^o

60^o + 105 ^o + + 90^o = 360^o

= 360^o – 255^o = 105^o

= 105^o

Step 1: Draw the side AB = 5.5 cm

Step 2: Draw = 60°

Step 3: Draw = 105°

Step 4: With B as centre and radius equal to 3.7 cm draw an arc and name the point as C

Step 5: With C as centre ,construct an angle 105° and mark the point of intersection of line AX and the angle 105° as point D

Step 6: Join the points C and D

ABCD is the required quadrilateral