Q17 of 805 Page 12

Construct a in which base BC = 4.8 cm, and (AB – AC) = 2.5 cm.

Step 1: The base BC = 4.8cm is constructed



Step 2: An angle of 45° is constructed at B



Step 3: 2.5cm length BD is cut off from the ray and points D and C are joined



Step 4: An angle equal to the exterior angle of D is constructed at C and the two rays are made to join at point A



∆ABC is the required triangle


BC = 4.8cm


BD = AB-AD = AB-AC = 2.5cm


<B = 45°


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