Q6 of 805 Page 1

A network of resistors is connected to a 16 V battery with an internal resistance of 1 as shown in the following figure. Compute the equivalent resistance of the network.


OR


A 9 V battery is connected in series with a resistor. The terminal voltage is found to be 8 V. Current through the circuit is measured as 5 A. What is the internal resistance of the battery?


The equivalent resistance between AB is ,
between CD is
,


So, the net resistance of the circuit is 2+1+4+1=8 Ω


OR


The equivalent resistance of the circuit is R + r Ω.


The current in the circuit as per ohm’s law is,




So, we can write,



Also, the terminal voltage across the resistor is 8 V, so,


R × 5 = 8,



Substituting the value of R in (1),





So, the internal resistance of the cell is .


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