A network of resistors is connected to a 16 V battery with an internal resistance of 1 Ω as shown in the following figure. Compute the equivalent resistance of the network.

OR
A 9 V battery is connected in series with a resistor. The terminal voltage is found to be 8 V. Current through the circuit is measured as 5 A. What is the internal resistance of the battery?

The equivalent resistance between AB is
,
between CD is
,
So, the net resistance of the circuit is 2+1+4+1=8 Ω
OR
The equivalent resistance of the circuit is R + r Ω.
The current in the circuit as per ohm’s law is,

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So, we can write,
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Also, the terminal voltage across the resistor is 8 V, so,
R × 5 = 8,
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Substituting the value of R in (1),

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So, the internal resistance of the cell is
.
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