Q14 of 805 Page 12

Construct a in which BC = 5.2 cm, and the difference of the other two sides is 3.5 cm.

Steps of Construction:


1. Draw BC = 5.2 cm



2. Construct ∠ CBX = 30°



3. Along BX set off BP = 3.5 cm



4. Join PC



5. Draw perpendicular bisector of PC meeting BP produced at A.



6. Join AC.



Therefore, Δ ABC is the required triangle.


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Construct a in which BC = 4.5 cm, and the sum of the other two sides is 8 cm.

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