Q29 of 805 Page 1

Prove that the tangents at any point of a circle is perpendicular to the radius through the point of contact.


In the given figure, AB is a tangent at point of contact C


D is an arbitrary point on tangent AB. Connect O with D and


E be the point on line OD on circle.


OE < OD


OC < OD (because OE and OC is radius)


So, we can say that every line from centre of circle to


tanget is greater than radius at point of contact. It means


that radius is shortest line that touches the tangent.


And we know that shortest line is always perpendicular.


So, OC AB


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