Draw a right triangle in which the sides (other than hypotenuse) are of lengths 4 cm and 3 cm. Then, construct another triangle whose sides are
times the corresponding sides of the given triangle.
Steps of Construction:
1. Draw base AB of side 3 cm.
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2. Draw ∠ A = 90°

3. Taking A as center, 4 cm as radius, we draw an arc. Let the point where the arc intersects the ray be point C.

4. Join BC.

Δ ABC is the required triangle.
Now, we need to make a triangle which is
times its size.
Scale factor ![]()
Steps of Construction:
1. Draw any ray AX making an acute angle with AB on the side opposite to the vertex C.

2. Mark 5 (greater of 5 and 3) points B1, B2, .., B5 on AX so that AB1 = B1B2 = .. = B4B5.

3. Join B3B and draw a line parallel to B3B, to intersect AB extended at B’.

4. Draw a line through B’ parallel to the line BC to intersect AC extended at C’.

Thus, Δ A’BC’ is the required triangle.
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