The first and last terms of an A.P. are 8 and 350 respectively. If it’s common difference is 9, how many terms are there and what is their sum?
OR
How many multiple of 4 lie between 10 and 250? Also find their sum.
Given that a = 8, Tn = 350 and d = 9
To find n and Sn
Tn = a + (n – 1)d = 350
8 + (n – 1)(9) = 350
n = 39
Sn = n/2(2a + (n – 1)d)
= 39/2(2×8 + (39 – 1)9)
= 6981
OR
The first number which is multiple of 4 and greater than 10 is 12 and the second number which is multiple of 4 is 16.
The last number which is less than 250 and multiple of 4 is 248.
It becomes an A.P with first term 12 and common difference 4.
A.P. ⇒ 12, 16, 20, ……, 248
We know, if a and d are first term and common difference of an AP respectively, nth term equals
Tn = a + (n – 1)d
248 = 12 + (n – 1)4
n = 60
Also, sum of first n terms is
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= 30(24 + 59×4)
= 7800
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