Construct a triangle PQR with sides QR = 7 cm, PQ = 6 cm and . Then construct another triangle whose sides are 3/5 of the corresponding sides of .

The steps involved in the required construction are:

1) Draw a line segment PQ=6 cm.

2) Using a protractor, draw ∠PQA=60°. Taking Q as the center and radius 7 cm, draw an arc, intersecting QA at R. Join PR.

3) Draw any line segment QB, making an acute angle with PQ and opposite to the vertex R. Taking Q as the center and any radius, draw an arc, intersecting QB at C. Taking C as the center and radius QC, draw an arc, intersecting QB at D. Similarly, repeat the process 3 more times to get points E, F and G. Join PG.

4) Taking G as the center and any radius, draw an arc., intersecting QB and PG at H and I respectively. Taking E as the center and radius GH, draw an arc, intersecting QB at J. Taking J as the center and radius HI, draw an arc, intersecting previous arc at K. Join and extend EK, intersecting extended PQ at L.

5) Taking P as the center and any radius, draw an arc., intersecting PQ and PR at N and O respectively. Taking L as the center and radius PN, draw an arc., intersecting PQ at S. Taking S as the center and radius NO, draw an arc, intersecting previous arc at T. Join and extend LT, intersecting QR at M.

6) ∆QLM is the required triangle.