Q5 of 805 Page 17

Prove that the diagonals of a rhombus bisect each other at right angles.


ABCD is a rhombus . → AB = CD


Also, diagonals bisects each other → DO = OB


AO is common . So,


Triangle AOD is congruent to triangle AOB


So , Angle AOD = Angle AOB …… (C.P.C.T)


But , Angle AOD + Angle AOB = 180 …… (Linear pair)


So , Angle AOD = Angle AOB = 90


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