Q4 of 805 Page 13

Construct a triangle with sides 5 cm, 6 cm and 7 cm and then another triangle whose sides are of the corresponding sides of the first triangle.


Steps of Construction:


1. Draw a line segment QR = 7 cm.



2. With Q as centre and radius 5 cm, draw an arc.



3. With R as centre and radius 6 cm, draw an arc cutting the previous arc at P.



4. Join PQ and PR. Thus, ΔPQR is the required triangle.



5. Below QR, draw an acute angle ∠RQX.



6. Along QX, mark 7 points R1, R2 … R7 points such that QR1 = R1R2 … = R6R7



7. Join R5R and draw a line through R7 parallel to R5R, to intersect QR extended at R’.



8. Draw a line through R’ parallel to the line PR to intersect QP extended at P’.



Thus, Δ P’QR’ is the required triangle.


More from this chapter

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