Q7 of 805 Page 11

Draw a right triangle in which the sides (other than hypotenuse) are of lengths 4 cm and 3 cm . Then construct another triangle whose sides are times the corresponding sides of the given triangle.

Draw a line BC=5cm


At point B, construct a right angle.


Take a another point which away 4cm through point B.


Now join AC.


Now, draw a ray BX.


Join B3C.


Draw a parallel line through B5 to B3C, Get point C’


B5C’, draw a parallel line to AC.


∆A'BC' is required triangle.



Justification:


∠B=90°


∠C=∠C'


∆A'BC'~ ∆ABC






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