Q6 of 805 Page 13

Draw a ΔABC, right-angled at B such that AB = 3 cm and BC = 4 cm. Now, construct a triangle similar to ΔABC, each of whose sides is times the corresponding side of ΔABC.


Steps of Construction:


1. Draw a line segment BC = 4 cm.



2. Draw a perpendicular from point B.



3. Draw an arc of length 3 cm from B and let it intersect the perpendicular at A.



4. Join AC.



5. Δ ABC is the required triangle.


6. Draw a ray BX in the side opposite to the vertex A such that ∠ CBX is acute.



7. Along BX, mark 7 points C1, C2... C7 such that BC1 = C1C2 = … = C6C7.



8. Join C5C.



9. Draw C7C’ parallel to C5C such that it meets the extended BC at C’.



10. Draw C’A’ parallel to AC such that it meets the extended BA at A’.



Δ A’BC’ is the required triangle whose are times the corresponding side of Δ ABC.


More from this chapter

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Construct a ΔABC in which BC = 5 cm, ∠C = 60° and altitude from A equal to 3 cm. Construct a ΔADE similar to ΔABC such that each side of Δ ADE is times the corresponding side of ΔABC. Write the steps of construction.

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