Q3 of 805 Page 18

Construct a quadrilateral ABCD when AB = 3 cm, CD = 3 cm, DA = 7.5 cm, AC = 8 cm and BD = 4 cm.

As three sides and two diagonals of quadrilateral is given.

Step 1-Using SSS construction condition first we will draw ΔACD. Draw line


AC of length 8 cm.



Step 2- Then using compass take a length of 7.5 cm and draw an arc by taking A as centre. Do the same by taking C as centre and length of 3 cm.


Step 3-Now join the intersection point to A and C and label it as D.



Step 4- Now for vertex B, using compass take a length of 4 cm and draw an arc by taking D as centre. Do the same by taking A as centre and length of 3 cm.



Step 5-As arcs drawn are not intersecting it is not possible to construct quadrilateral ABCD (as in ΔABD, BD+AB< AD).


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1

Construct a quadrilateral ABCD in which AB = 3.8 cm, BC = 3.0 cm, AD = 2.3 cm, AC = 4.5 cm and BD = 3.8 cm.

 2

Construct a quadrilateral ABCD in which BC = 7.5 cm, AC =AD = 6 cm, CD = 5 cm and BD = 10 cm.

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Construct a quadrilateral ABCD given AD = 3.5 cm, BC = 2.5 cm, CD = 4.1 cm, AC = 7.3 cm and BD = 3.2 cm.

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Construct a quadrilateral ABCD given AD = 5 cm, AB = 5.5 cm, BC = 2.5 cm, AC = 7.1 cm and BD = 8 cm.