Q1 of 805 Page 17

Construct a Δ ABC in which BC=3.6 cm, AB+AC=4.8 cm and ∠B = 60°.

The steps of the required construction are:

1) Draw a line segment BC=3.6cm. Using a protractor, draw ∠CBD=60°. Join and extend BD.



2) Taking B as the center and radius=4.8cm, draw an arc, intersecting extended BD at point P. Join PC.



3) Taking P as the center and radius greater than , draw arcs on each side of PC. Now, taking C as the center and same radius, draw arcs, intersecting the previous arcs at points Q and R. Join and extend QR. Extended QR intersects line segment DB at point A. Join AC.



4) ∆ABC is the required triangle.


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Construct a Δ ABC in which AB+AC=5.6 cm, BC=4.5 cm, and ∠B = 45°.

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