Q5 of 805 Page 13

Construct a ΔABC with BC = 7 cm, ∠B = 60° and AB = 6 cm. Construct another triangle whose sides are times the corresponding sides of ΔABC.


Steps of Construction:


1. Draw a line segment AB = 6 cm.



2. With B as the center, draw ∠ B = 60°



3. With B as centre and radius BC = 7 cm, draw an arc to intersect the previously drawn line.



4. Mark the intersection point as C and join AC to get Δ ABC.



5. Below AB, make an acute angle ∠ BAX.



6. Along AX, mark off four points B1, B2, B3, B4 such that AB1 = B1B2 = B2B3 = B3B4.



7. Join B4B.



8. From B3, draw B3B’ || B4B.



9. From B’, draw B’C’ || BC.



Thus, Δ AB’C’ is the required triangle with each of its side times the size of the corresponding sides of Δ ABC.


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