Construct a in which base BC = 5.2 cm, and (AB + AC) = 7.6 cm.

Step 1: Base BC of length 5.2cm is constructed

Step 2: Construct an angle of 60° at B

Step 3: Cut off BD = 7.6cm on this ray of the angle and join points D and C

Step 4: An angle equal to <BDC is constructed at C and the ray meets the line segment BD at A to give the required triangle

∆ABC is the required triangle.

BC = 5.2cm

BD = BA+AD = BA+AC = 7.6cm

<ABC = 60°