Construct a quadrilateral PQRS where PQ = 3.5 cm, QR = 6.5 cm, ∠P = ∠R = 105° and ∠S = 75°.
We know that sum of all angles in a quadrilateral is 3600
+
+
+
= 360o
105o +
+ 75 o + 105 o = 360o
= 360o – 285o = 75o
= 75o
Step 1: Draw the side PQ = 3.5 cm

Step 2: Draw
= 105°

Step 3: Draw
= 75°

Step 4: With Q as centre and radius equal to 6.5 cm draw an arc and name the point as R

Step 5: With R as centre ,construct an angle 105° and mark the point of intersection of line PX and the angle 105° as point S

Step 6: Join the points R and S

PQRS is the required quadrilateral
Couldn't generate an explanation.
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