Q29 of 805 Page 257

Factorize: a3 – b3 + 1 + 3ab

Given, a3 – b3 + 1 + 3ab

⇒ a3 + (-b)3 + 13– 3(1 * a * (-b))


⇒ [a + (-b) + 1] [a2 + (-b)2 + 12 – a(-b) – (-b)1 – 1a]


⸫ (a – b + 1) (a2 + b2 + 1 + ab + b – a)


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