Construct a triangle similar to a given such that each of its sides is of the corresponding sides of . It is given that AB = 5 cm, BC = 7 cm and .

The steps involved in the required construction are:

1) Draw a line segment BC=6 cm.

2) Using a protractor, draw ∠CBD=50°. Taking B as the center and radius 5 cm draw an arc, intersecting BD at A. Join AC.

3) Draw any line segment BE, making an acute angle with BC and opposite to the vertex A. Taking B as the center and any radius, draw an arc, intersecting BE at F. Taking F as the center and radius BF, draw an arc, intersecting BE at G. Similarly, repeat the process 5 more times to get points H, I, J, K and L. Join CL.

4) Taking L as the center and any radius, draw an arc., intersecting BE and CL at M and N respectively. Taking J as the center and radius LM, draw an arc., intersecting BE at O. Taking O as the center and radius MN, draw an arc, intersecting previous arc at P. Join and extend JP, intersecting BC at Q.

5) Taking C as the center and any radius, draw an arc., intersecting BC and CA at S and T respectively. Taking Q as the center and radius CS, draw an arc., intersecting BC at U. Taking U as the center and radius ST, draw an arc, intersecting previous arc at V. Join and extend QV, intersecting AB at R.

6) ∆BQR is the required triangle.