Q27 of 805 Page 427

Evaluate:

Given: …Equation 1


We know


sec θ = cosec (900 – θ)


tan θ = cot (900 – θ)


sin θ = cos (900 – θ)


Using the above three relations in Equation 1 we get



We also know


sin2 θ + cos2 θ = 1


⇒ sin2 55 + cos2 55 = 1


And,


∴


⇒


⇒


⇒



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