A train travels 180 km at a uniform speed. If the speed had been 9 km/hour more, it would have taken 1 hour less for the same journey. Find the speed of the train.
OR
Find the roots of the equation
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Let, the distance covered by the train = d km
Speed of the train = s km/hour
And the time taken by the train = t hour
180 = s × t …(1)
180 = (s + 9) × (t – 1) ⇒
…(2)
From eq.(1) and eq.(2)
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180s + 1620 = 189s + s2
s2 + 9s – 1620 = 0
(s – 36)(s + 45) = 0
s = 36 and -45
But, speed of train is neither be negative.
So, speed of train is 36 km/hour.
OR
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⇒ 3x – 8 = 2x2 – 13x + 15
⇒ 2x2 – 16x + 23 = 0
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⇒
and ![]()
So, the roots of the equation are
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