Construct a
in which
and the length of the perpendicular from the vertex A to the base BC is 4.8 cm.
Steps of Construction:
1. Draw a line segment AB.

2. Take any point C on AB and draw CD perpendicular to AB.

3. Along CD, set CE = 4.8 cm.

4. Through E, draw PQ parallel to AB.

5. Construct ∠ PEX = 30° and ∠ QEY = 60° meeting AB at X and Y respectively.

Therefore, Δ XEY is the required triangle.
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