Q5 of 805 Page 11

A rhombus whose diagonals are 4 cm and 6 cm in lengths.

Step 1:


Draw a line AX and with A as center and radius 6cm cut an arc on AX at C.



Step 2:


Construct perpendicular bisector of AC and name it as PQ.


Name the intersecting point O.



Step 3:


With O as the center and radius 2cm draw arcs to cut OP and OQ at D and B respectively.



Step 4:


Join AB,BC,CD and DA.



Justification


AC=6cm (By Construction)


PQ is perpendicular to AC (By Construction)


As AC=6cm is one the diagonals So BD is the other diagonal with length 4cm.


As it is a rhombus we know that the diagonals bisect each other so


So, OD=OB=2cm.


Thus our construction is justified.


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