Q5 of 805 Page 11

Draw a line segment AB of length 8 cm. Taking A as Center, draw a circle of radius 4 cm and taking B as center, draw another circle of radius 3 cm. Construct tangents to each circle from the Center of the other circle.

Step1: Draw a line PQ=8cm. taking P and Q as a center draw circle of 3cm and 4cm.


Step2: Now bisect PQ. We get midpoint of PQ be T.


Now take T as a center , draw a circle of PT radius , this will intersect the circle at point A,B,C,D. Join PB,PD,AQ,QC.



Justification:


It can be justified by prove that PB,PD are tangents of circle (whose center is P and radius is 3cm) and AQ,QC are tangents of circle (whose center is Q and radius is 4cm)


Join PA, PC, QB, QD


∠PBQ=90° (Angle is on semicircle)


BQ⊥PB


Since, BQ is radius of circle, PB has to be a tangent. Similarly PD, QA ,QC are tangents.


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